Featured René Lalique Vase "Penthievre"

Sometimes.
Often it's easier to call them back to see their (probably forgotten) thread here, by putting an "@" sign before their name and clicking on it. This will cause them to receive an email to let them know they have messages here. Like this:

@Sdcookie2

 

@Sdcookie2 , was here Sat night.....

just cuz a member doesn't post .....does not mean that they have forgotten or are ignoring their thread...or answers.!!

 

Agree. Also if someone responds to a thread I've posted, or even if someone tags me with the "@" before my name, I (like many others here) receive zero notifications from the site, so no alert. Email alerts used to work perfectly for years, no changes on my end, same computer, same browser. I have to go in and manually check and many a time I thought a thread was concluded only to find more responses I had no idea were there.

So in some cases may be that the poster is expecting an alert. And assumes no alert means no responses.

 

and again yesterday ...

which is why I asked ...
them having been a member for 4 years, I mistakingly assumed they followed their requests for info..

 

It doesn’t bother me, I learn a lot from the threads here

 

we've had problems with notifications across the board.....
I too no longer get emails if I'm tagged except for PM's......

 

Thanks for the tag. I haven't received notifications for some time now.
As for responding to this thread, I wasn't asking for anyone's advice. Therefore no response. The piece was purchased from an Antiques Roadshow glass appraiser, so I already knew it was genuine. Actually just sold it two days ago to a gallery in France.
I generally thank people who help out.

 

same, thanks all

 

I do. I am awed at the generosity of spirit of the members who take their time & effort to help me.

 

I also don't get Email Alerts anymore,so I just travel up to the upper right-hand corner (to above my Avatar & the 'Search Bar'),and click on 'Inbox' and 'Alerts', brings me up to speed just fine (i think ?)

 

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